x = total amount of students in 8th Grade.
we know only one-thrid of the class went, so (1/3)x or x/3 went.
we also know 5 coaches went too, and that the total amount of that is 41.

now, to verify, well, what do you get for (108/3) + 5?
We are given these three people age below:
- Jim's age
- Carla's age
- Tomy's age
We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.
Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.
Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).
The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

Combine like terms and solve for x.

Then we substitute the value of x in ages to find these three people ages.
- Jim's age = x = 5
- Carla's age = x+5 = 5+5 = 10
- Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.
Answer
- Jim's age = 5
- Carla's age = 10
- Tomy's age = 16
Answer:
8 and 19
Step-by-step explanation:
To some this, let's first list all the factors of 152. They are;
1, 2, 4, 8, 19, 38, 76, 152.
Now, let's arrange them to reflect being multiplied to get 152.
Thus;
1 × 152 = 152
2 × 76 = 152
4 × 38 = 152
8 × 19 = 152
Also, let's do the same for their sum;
1 + 152 = 153
2 + 76 = 78
4 + 38 = 42
8 + 19 = 27
Looking at the figures above, the ones that their product is 152 but have the least sum are 8 and 19
The distance between -6 and -3 on a number line is 3.