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Aliun [14]
3 years ago
6

Simplify 1/2√40 A) √10 B) 2√10 C) 4√10

Mathematics
2 answers:
const2013 [10]3 years ago
7 0

\frac{1}{2}  \sqrt{ {2}^{2} }  \times \sqrt{10}
that is:
1/2 * 2 *√10

= √10 therefore Option A is correct

Len [333]3 years ago
3 0
It would br A)√10
If you want the work tell me.
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Look at the figure. How can you prove ∆ABD and ∆ACD are congruent?
Levart [38]

Answer:

Options (C)

Step-by-step explanation:

For the congruence of the triangles ΔADB and ΔADC,

                Statements                             Reasons

1). AB ≅ AC                                   1). Given

2). AD ≅ AD                                 2). Reflexive property

3). ∠BAD ≅ ∠CAD                       3). Given

4). ΔABD ≅ ΔCAD                       4). SAS postulate

Therefore, Options (C) will be the correct option.

7 0
3 years ago
An u guys help me with -2f+3-2f-8
vredina [299]

Answer:

-4f-5

Step-by-step explanation:

M

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5 0
3 years ago
Julia has 2 identical rooms in her house. if each room measures 8 feet on one side and 12 feet on another, what is the total are
Jlenok [28]
First we have the work out the area of 1 room. So that is 8ft * 12ft which is 96ft^2. And if there are 2 of these rooms, then we multiply this value by 2. Giving us a total area of 192ft^2.
5 0
3 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
What is the answer to 2 1/4 x 3 1/9
vlada-n [284]
2 1/4 times 3 1/9

Make the fractions into decimals

So now it’s 2.25 times 3.11...

Multiply that to get 6.99 but since the 3.11... is a repeated sequence you would round it to 7, which is your answer!
3 0
2 years ago
Read 2 more answers
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