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Charra [1.4K]
3 years ago
6

x^2y^2 + 5y^4" align="absmiddle" class="latex-formula"> from 2x^4-8x^2y^2-y^4
Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

the answer to the question is 8x⁴- 5x²y² - 6y⁴  

Step-by-step explanation:

the normal way of using BODMAS is apply to all polynomial equations.

subtracting  -6x⁴- 3x²y² + 5y⁴ from 2x⁴ - 8x²y² - y⁴.

polynomial of the same degree is very easy to calculate. this equation is having the same degree of polynomial all through, therefore:

  Applying Bracket to the equation

   2x⁴ - 8x²y² - y⁴- ( -6x⁴- 3x²y² + 5y⁴)

  Open the bracket

   2x⁴ - 8x²y² - y⁴ +6x⁴+3x²y² - 5y⁴

  collects the likes terms

   2x⁴ +6x⁴- 8x²y² +3x²y² - 5y⁴  - y⁴

  The final answer is =

   8x⁴- 5x²y² - 6y⁴  

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3 years ago
H(x)= (x^2 -36)/x +6 explain why the following function is not continuous at x=-6
sergeinik [125]

You can solve this problem through factoring.

First, you have the equation,

h(x) = \frac{x^2-36}{x-6}

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8 0
3 years ago
The square of a negative number is twenty-eight more than three times the negative number. Find the number.
MAXImum [283]
The number is x

it is negative
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minus (28+3x)
x²-3x-28=0
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set to zero

x-7=0
x=7
this is not the answer because we were told the number was negative


x+4=0
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correct

the number is -4
test
(-4)²=28+3(-4)
16=28-12
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check


the number is -4
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