Answer:

Step-by-step explanation:
We want to create a third degree polynomial function with one zero at three.
In other words, we want to find a polynomial function with roots x=3 , multiplicity, 3.
Since x=3 is a solution, x-3 is the only factor that repeats thrice.

We expand to get:


This simplifies to:

See attachment for graph.
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<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em>.</em><em>=</em><em>)</em>
Whats the question? we cant help you if you dont give us the question.
We look for the minimum of each function.
For f (x) = 3x2 + 12x + 16:
We derive the function:
f '(x) = 6x + 12
We match zero:
6x + 12 = 0
We clear the value of x:
x = -12/6
x = -2
We substitute the value of x in the equation:
f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
f (-2) = 4
For g (x) = 2sin(x-pi):
From the graph we observe that the minimum value of the function is:
y = -2
Answer:
A function that has the smallest minimum y-value is:
y = -2