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Reptile [31]
4 years ago
11

What is the distance between (8,-6) and (-1,-6)

Mathematics
2 answers:
MissTica4 years ago
3 0
19 is the distance between those 2
frez [133]4 years ago
3 0
The Pythagorean Theorem states that:

h^2=x^2+y^2

Which just means that the square of the hypotenuse, or longest side of a triangle is equal to the sum of the squares of the two other sides...

Often it is just called the "distance formula" because it is used so often in that context...

In this case we wish to know the distance between two points and the equation becomes...

d^2=(y2-y1)^2+(x2-x1)^2

d^2=(-6--6)^2+(-1-8)^2

d^2=(0)^2+(-9)^2

d^2=81, since d>0

d=+√81

d=9 units
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Can someone please help
Sliva [168]

Answer:

i got no clue

Step-by-step explanation:

ignc

4 0
3 years ago
Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.
andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

The equation is given as: \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0
3 years ago
Mr. smith has 5 courses he teaches at the community college. his course a has 102 students with an average tardiness of 3 studen
Furkat [3]

The percentage of tardiness among the 102 pupils is 2.94.

<h2>Calculation of the percentage</h2>

According to the query,

Course A: Total number of students = 102

                   Number of tardy students = 3

Percent of students tardy in course A = (number of tardy students/total  

                                                                   number of students) * 100

  =(3/102)*100

  = 2.941

  ≈2.94

In case of course B: Total number of students = 85 & tardy student = 5

So, the percent of tardy student = (5/85)*100 = 5.88 %

Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.

Learn more about the percentage here:

brainly.com/question/92258

#SPJ4

5 0
2 years ago
A bowl of mixed vegetables contains carrots, broccoli, and cauliflower. If the bowl contains 80 vegetable pieces, and 25% of the
LekaFEV [45]
There are 20 carrots because 25% of 80 is 20
5 0
4 years ago
Read 2 more answers
Solve (get the variable by itself): m / (-4) = -2.95
kenny6666 [7]
M / -4 = -2.95
As you can see, the variable m is currently in a fraction with a denominator of -4. So to get ride of the fraction and find m and its value, you should multiply both sides by the denominator of the fraction, which is in our case -4.
So m / -4 = -2.95
(m/-4) * -4 = -2.95 * -4
m = 11.8

You can recheck your answer (very important):
m / -4 = 11.8 / -4 = -2.95
The answer has been approved.

Hope this Helps! :)
7 0
3 years ago
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