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STALIN [3.7K]
3 years ago
13

A recursive rule for a geometric sequence is a1=8; an=3/4a n−1 . What is the explicit rule for this sequence?

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0
A(n) =(3/4)x a(n-1)


for n =1==> a₁ =8
Give for n, the value 2,3,4 etc.

for n=2==>a₂ = 3/4(a₁) = 3/4 (8) = 6
for n=3 ==>a₃ =3/4(a₂) = 3/4(6) = 9/2
for n=4 ==>a₄ =3/4(a₃) = 3/4(9/2)
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
and for n=n ==>a(n) =(3/4)(a(n-1)
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Answer:

a) the sample size is 400

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Step-by-step explanation:

Given the data in the question;

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a)

n = 400

Hence, the sample size is 400

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At 95% confidence interval,

significance level ∝ = 1 - 95% = 1 - 0.95 = 0.05

∝/2 = 0.05 / 2 = 0.025

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So for Confidence Interval for p;

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we substitute

⇒ 0.05 ± 1.96√( (0.05 × 0.95 ) / 400 )

⇒ 0.05 ± 1.96√( 0.00011875 )

⇒ 0.05 ± 1.96 × 0.010897

⇒ 0.05 ± 0.021358

⇒ ( 0.05 - 0.021358 ), ( 0.05 + 0.021358 )

⇒ ( 0.0286, 0.0714 )

Therefore, 95% confidence Interval for p is ( 0.0286, 0.0714 )

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