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3 years ago

6

The length of a rectangle is 4 units more than its width. The area of the rectangle is 25 more than 4 times the width. What is t

he width of the rectangle?

1 answer:

mote1985 [20]3 years ago

8 0

Answer:

Step-by-step explanation:

4w+25=w^2+4w

So w =5

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Sign the following values a=5 b=10 c=15

a_sh-v [17]

Answer:

a=5,b=10,c=15

1)(a+b)-5(c+a)

=(5+10)-5(15+5)

=(15)-5(20)

=15-5(20)

=10(20)

=200

2)(10×15)10(5×2)

=150×10×10

=15000

3)(a-b)+(a+b)

(5-10)+(10+5)

(-5)+15

-5+15

=10

4)(2ab-45)+a

=(2×5×10-45)+5

=(100-45)+5

=55+5

=60

7 0

2 years ago

Juan and his father went on a driving trip.

Jet001 [13]

Answer:

162

Step-by-step explanation:

260/2=130

130+32=162

8 0

3 years ago

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ANSWER THIS QUICK QUESTION FOR 16 POINTS!

salantis [7]

I believe it's C E.

They both look pretty equal and line up perfectly with E. Hope this helps!

7 0

3 years ago

HELPPPP please !!!!!,!!?

lions [1.4K]

Mercury has the greater density than that of Venus .

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3 years ago

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Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul

umka21 [38]

Answer:

The number of calculators is 4871

Step-by-step explanation:

If we integrate dx/dt we get x, which is the number of calculators. To find the number of calculators between the beginning of third week to the end of fourth week (the beginning of fifth week), this integration must be evaluated at t between 3 and 5.

$x=\int\limits^5_3 {\frac{dx}{dt}} \, dt =\int\limits^5_3 {5000(1-\frac{100}{(t+10)^2})} \, dt$

the result of the integration is:

$x=5000(t+\frac{100}{t+10})$ to be evaluated between 3 and 5, which is:

$x=5000(5+\frac{100}{5+10})-5000(3+\frac{100}{3+10})=\frac{190000}{39}=4871.8$

6 0

3 years ago