The equation modeling the height of the ball at time,t is given by h=-16t²+48t+6
<span>a. In how many seconds does the ball reach its maximum height?
Time taken for the ball to reach the maximum height will be given by:
h'(t)=-32t+48=0
finding the value of t we get:
32t=48
t=48/32
t=1.5 seconds
Thus the time taken for the ball to reach the maximum time is 1.5 seconds
b]</span><span> What is the ball’s maximum height?
The maximum height will be:
h(1.5)=-16(1.5)</span>²+48(1.5)+6
h(1.5)=42 fee
In order to solve for the area of the triangle with the
given dimensions, we use the equation
<span> A
= ac(cos b)/2</span>
Substituting the known values,
<span>
A = (11 cm)(18 cm)(cos 104o)/2 = 23.95 cm2</span>
<span>Thus, the answer is the third choice. </span>
Answer:
x³+1
Step-by-step explanation:
4x-8 | 4x⁴ - 8x³ + 4x - 8
<u>_4x⁴ - 8x³______</u> <-- x³
4x - 8
<u> 4x - 8</u> <-- 1
0 | x³+1
Therefore, (4x⁴-8x³+4x-8)/(4x-8) = x³+1
Answer:
14<15
Step-by-step explanation:
Any number less than 15 can work.
