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Roman55 [17]
3 years ago
13

Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

Answer:

Option a,d and e are true statements.  

Step-by-step explanation:

Given : Function f(x)=x^2-8x+5

To find : Which statements are true about the graph of the function, Check all that apply?

Solution :  

The quadratic function is in the form, y=ax^2+bx+c

The vertex form is y=a(x-h)^2+k

To find vertex form we apply completing the square,

f(x)=x^2-8x+5+4^2-4^2

f(x)=x^2-8x+(4)^2+5-16

f(x)=(x-4)^2-11

The vertex form of the function is f(x)=(x-4)^2-11

The 'a' statement is true.

The vertex of the function is (h,k).

On comparing with vertex form, h=4 and k=11

Vertex of the function is (4,11)

The 'b' statement is not true.

The x-coordinate of the vertex i.e. x=-\frac{b}{2a} is the axis of symmetry,

So, x=-\frac{-8}{2(1)}

x=4

The axis of symmetry is x=4.

The 'c' statement is not true.

The y-intercept of the function is at x=0

So, Put x=0 in the equation f(x)=x^2-8x+5

f(0)=0^2-8(0)+5

y=5

The y-intercept of the function is (0,5).

The 'd' statement is true.

To find the function crosses the x-axis twice refer the attached figure below.

Yes the function crosses the x-axis twice.

The 'e' statement is true.

gregori [183]3 years ago
4 0
D. The y-intercept of the function is (0, 5) and e. The function crosses the x-axis twice are true
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Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1&gt;3 SUVs per month, where t is time in mon
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The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

S'(t)=-24^{1/3} SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given S'(t)=-24^{1/3} ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from S'(t)=-24^{1/3}

\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\

On Integrating both sides

S(t)=-18t^{4/3}+c ~...~...~(2)

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

\thereforefrom eq (2)

S(t)=-18t^{4/3}+1200 ~...~...~(3)

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) 300=-18t^{4/3}+1200

t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

#SPJ10

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