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3 years ago

The difference between 7 and the product 3x is 23. Please help me ASAP

Mathematics

1 answer:

loris [4]3 years ago

5 0

3x-7=23 should be your equation I think so 3x= 30 X=10

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1 1/2 years is how many months

Elan Coil [88]

18
12 + 6 = 18
There Are 12 In One Year.

3 0

3 years ago

Read 2 more answers

Dennis_Churaev [7]

First you have to know, that the price the agent found is 70% of $2075
(100%-30%=70%)
70%=0,7
$2075 * 0,7 = $1452,5
So 70% 0f $2075 is 1452,5

The price the agant found is $1452,5.

5 0

4 years ago

the length of a rectangle is five feet less than its width. If the area of the rectangle is 84 square feet, find its dimensions

KIM [24]

Let
x---------> the length of the rectangle
y--------> the width of the rectangle

we know that
A=84 ft²
[area of rectangle]=x*y-----> 84=x*y-----> equation 1
x=y-5------> equation 2
substitute 2 in 1
84=[y-5]*y-----> 84=y²-5y---------> y²-5y-84=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is
y=12
x=y-5-----> x=12-5-----> x=7

the answer is
the length of the rectangle is 7 ft
the width of the rectangle is 12 ft

6 0

3 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete sidewalk surrounds the pool and is a constant 2 fee

Naddika [18.5K]

Answer:

The dimensions of the pool are:

Width: 8.944 feet

Length: 17.888 feet

Step-by-step explanation:

From Geometry, the area of a rectangle ( $A$ ), measured in square feet, is determined by the following equations:

$A = w\cdot l$ (1)

Where:

$w$ - Width, measured in feet.

$l$ - Length, measured in feet.

If we know that $w = x$ , $l = 2\cdot x$ and $A = 160\,ft^{2}$ , then we get the following second order polynomial:

$2\cdot x^{2}-160 = 0$ (1)

And we solve the expression for $x$ :

$2\cdot x^{2} = 160$

$x^{2} = 80$

$x = \sqrt{80}\,ft$

$x \approx 8.944\,ft$

Then, the dimensions of the pool are, respectively:

$w \approx 8.944\,ft$ and $l \approx 17.888\,ft$

5 0

3 years ago

You want to make a rectangular banner that is 18ft. Long with a trim around the entire border of the banner . You have no more t

lys-0071 [83]

Answer:

6 ft

Step-by-step explanation:

Given that:

Length of rectangular banner = 18 ft

Total trim of banner available = 48 ft

To find:

Possible widths of the banner = ?

Solution:

Maximum trim available of the banner around the entire border of the banner = 48 ft

i.e. we are given the total perimeter of the rectangular banner.

Formula for perimeter of a rectangle is given as:

$Perimeter = 2 \times (Length + Width)$

Putting the values of perimeter and length to find the value of width.

$48 = 2 \times (18 + Width)\\\Rightarrow 48 =36+2 \times Width\\\Rightarrow 2 \times Width = 48-36\\\Rightarrow 2 \times Width = 12\\\Rightarrow \bold{Width = 6\ ft}$

So, width possible is <em>6ft.</em>

3 0

4 years ago