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Ilia_Sergeevich [38]
3 years ago
14

Is 7.7 greater less than or equal to 7.5

Mathematics
2 answers:
crimeas [40]3 years ago
6 0
7.7 is greater than 7.5
Andreyy893 years ago
4 0
Hey there, 7.7 is greater than 7.5
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9 packages of grape cost $24 how many packages of grapes can you buy for $8
Leto [7]
Ok. First you have to find the unit rate. Since you can buy 9 packages of grapes for $24, then you can get 1 grape package for $2.6667. If you have $8, you can buy 3 packages of grapes.
8 0
3 years ago
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The volume of a suitcase is 4.2 cubic feet. what is the volume of a suitcase that is smaller by a factor of 0.9? round to the ne
ANEK [815]
The volume would be 0.9 x 4.2

This means it is 90% smaller

Don't forget to round the nearest tenth place. That's the first decimal, so you answer should only have 2 digits.
3 0
3 years ago
Mr.Jones owns a greenhouse. He planted 100 tomato plants. only 72 of those plants survived. Write this as a percentage,a decimal
Anarel [89]
72/100=72%=0.72
Plants survived divided by total plants.
8 0
3 years ago
It's early in the evening, and you're standing in your back yard waiting for the stars to come out. Before long, you can see two
oee [108]
No star is higher; they're the same.
y = 10x + 30
Substitute "9x + 40" with y.

Then you get 9x + 40 = 10x + 30.
Get the variables on one side and the numbers on one side.
Basic algebra used here subtract 9x from both sides. Then subtract 30 from both sides and you will get x = 10.

Plug 10 for X into the equation and you will get Y = 130. Try each problem separately and you will get the same answer for both so they're equal, none is higher.
7 0
4 years ago
How do you simplify sin^4-cos^4=2sin^2-1?
Naily [24]

\bf \textit{Double Angle Identities} \\\\ cos(2\theta)= \begin{cases} cos^2(\theta)-sin^2(\theta)\\ 1-2sin^2(\theta)\\ 2cos^2(\theta)-1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \begin{array}{llll} sin^4(\theta )-cos^4(\theta )&=&2sin^2(\theta )-1\\[1em] [sin(\theta )]^4-[cos(\theta )]^4&=&-[1-2sin^2(\theta )]\\[1em] \stackrel{\textit{difference of squares}}{[[sin(\theta )]^2]^2-[[cos(\theta )]^2]^2}&=&-[cos^2(\theta )-sin^2(\theta )]\\[1em] [sin^2(\theta )-cos^2(\theta )][sin^2(\theta )+cos^2(\theta )]&=&sin^2(\theta )-cos^2(\theta )\\[1em] [sin^2(\theta )-cos^2(\theta )][1]&=\\\\ sin^2(\theta )-cos^2(\theta ) &=\end{array}

8 0
3 years ago
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