All categories

3 years ago

Suppose Y varies directlly With x. If y= 6 when x=2 find x when y= 12

Mathematics

2 answers:

tia_tia [17]3 years ago

6 0

Answer: x=4

Step-by-step explanation:

By definition, the direct variation eqution has the following form:

$y=kx$

Where k is the constant.

Therefore, if If $y=6$ when $x=2$ , you can calculate k as following:

-Substitute values.

- Solve for k.

Then:

$6=k(2)\\k=3$

Then, when $y=12$ , you can calculate the value of x as it is shown below:

-Substitute values.

- Solve for x.

Then:

$12=3x\\x=4$

coldgirl [10]3 years ago

4 0

Answer:

The value of x = 4 when the value of y = 12

Step-by-step explanation:

∵ y α x ⇒ it is direct variation

- It means y increase when x increase

∴ y = kx ⇒ where k is a constant

- To find the value of k we will substitute the values of x

and y in the equation above

- If y = 6 when x = 2

∴ 6 = k(2) ⇒ divide two sides by 2

∴ k = 3

∴ y = 3x ⇒ equation of variation

- To find the value of x when y = 12

- Substitute the value of y in the equation of variation

∴ 12 = 3x ⇒ divide both sides by 3

∴ x = 4

* The value of x = 4 when the value of y = 12

You might be interested in

What unit would be best to use for measuring the weight of a stapler

Alenkinab [10]

GRAMS! Is the best answer :) all others are used for heavier objects and such, however GRAMS is just right for a light object as in a stapler

4 0

3 years ago

If you roll two dice, find the probability of rolling a sum equal to either six or eight.

Yanka [14]

Answer:

6/12=1/2 the probability of rolling q sum equal to either six or eight

5 0

3 years ago

Am i correct? calculus

Advocard [28]

Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer. That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

$\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\
$

$\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}$

8 0

3 years ago

PLEASE HELP ME!!! Graph the line with a slope of 2/3 that contains<br> the point (-3,-5).

uysha [10]

Answer:

y=2/3x-3

Step-by-step explanation:

first we fill in the values for y=2/3x to find y intercept

-5=2/3(-3)

-5=-6/3

-5=-2

We know in order to make this equation true we have to subtract 3 so we write the new equation like this

y=2/3x-3

And we can test it

-5=2/3(-3)-3

-5=-6/3-3

-5=-2-3

-5=-5

Hopes this helps please mark brainliest

5 0

1 year ago

Match the inequality to its graph.

EastWind [94]

4y+ 3 is greater than y+ 6

7 0

3 years ago