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pishuonlain [190]
4 years ago
6

Consider the expression. What is the result of applying the quotient of powers rule to the expression?

Mathematics
2 answers:
fenix001 [56]4 years ago
8 0

Answer:

Let us consider the expression:

\frac{a^5\cdot b^6}{a^2\cdot b^9}     (1)

Now, the quotient of power rules says that the numbers that have same base can be find by subtracting if powers are with same sign

And adding if powers are with opposite sign.

We will solve equation (1) by this quotient of power rule.

So, it can be rewritten as:

a^{5-2}\cdot b^{6-9}

\Rightarrow a^{3}\cdot b^{-3}.

 

Harlamova29_29 [7]4 years ago
7 0

If were talking about this equation

Then the answer on edg is C

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Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

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3 years ago
Describe the transformation from the graph of f(x)= x^3to the graph of g(x)=(x+1)3+12
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Step-by-step explanation:

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3 years ago
Find the nth term in the following sequence: 5, 7, 9, 11, 13...
vazorg [7]

Answer:

3=2n

Step-by-step explanation:

Formula: Tn=T1+(n-1)*d

Tn is the nth term

T1 is the first number of the sequence

n is the nth term as well

D is the common difference

now its Tn=5+(n-1)*2

now solve that so its

Tn=5+2n-2

now its

Tn=3+2n

that's it

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