The correct question is
What is the value of x in the following equation (1/5)^x=5^8
Applying logarithms both members
log(1/5)^x=log(5^8)
x*log(1/5)=8*log(5)
x=8*log(5)/log(1/5)
we know that
log (1/5)----> log (1)-log (5)----> 0-log (5)-----> -log (5)
so
x=8*log(5)/-log (5)------> x=-8
the answer is
-8
This reduced fraction would be c. x+y/8.
You can apply the Difference of Two Squares Formula (x^2+y^2)=(x+y)(x-y). Then, you can factor out the common term 8 and cancel out the common factor x-y. Hope this helps! :)
Answer:
x - 1 < n < 3x + 5
Step-by-step explanation:
If you have two sides of a triangle, the length of the third side is at least the difference between the other two sides, and at most the sum of the other two sides.
Answer:
£20
Step-by-step explanation:
1-1/4=3/4
3/4=15
1
1*15/3/4
15*4/3=20