Answer: C= -10
Step-by-step explanation: First step: simplify both sides of the equation
3c−2(c+10)=7c−5(c+2)
3c+(−2)(c)+(−2)(10)=7c+(−5)(c)+(−5)(2) (Distribute)
3c+−2c+−20=7c+−5c+−10
(3c+−2c)+(−20)=(7c+−5c)+(−10) (Combine Like Terms)
c + -20 = 2c - 10
c - 20 = 2c - 10
Step 2: Subtract 2c from both sides
c - 20 - 2c = 2c -10 - 2c
−c−20=−10
Step 3: Add 20 to both sides
−c−20+20=−10+20
−c=10
Step 4: Divide both sides by -1
-c/-1 = 10/-1
C=-10
- <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>
- <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>
According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.
<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>
<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>
The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse
Answer:
g=676
Step-by-step explanation:
g/13=52
We simplify the equation to the form, which is simple to understand
g/13=52
Simplifying:
+ 0.0769230769231g=52
We move all terms containing g to the left and all other terms to the right.
+ 0.0769230769231g=+52
We simplify left and right side of the equation.
+ 0.0769230769231g=+52
We divide both sides of the equation by 0.0769230769231 to get g.