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lbvjy [14]
3 years ago
6

60 minutes is 20% of minutes.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

60 minutes is 20% of 300 minutes

Step-by-step explanation:

let x be the number of total minutes

60 = 20% of x

20% = 1/5

60 = 1/5x

multiply both sides by 5

300 = x

x = 300 minutes

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How many vertices does the following shape have?
RSB [31]

Answer:

8

Step-by-step explanation:

each corner of the cube is a vertex

3 0
3 years ago
If it takes (a) men (b) hours to dig (c) holes, how many men are required to dig b holes in c hours?
docker41 [41]
Well, let's see . . .

You said that  (a) men can dig (c) holes in (b) hours.

So . . . It takes  (a) men  (b / c) hours to dig one hole.

And . . . It takes    One man  (a b / c) hours to dig one hole.

Now . . .  There are  (b) holes to be dug.

              It would take one man  (a b / c)·(b) = (a b² / c) hours to dig them all.

              But if you had 'x' men, it would only take them  (c) hours to do it.

So          c  =  (a b² / c)  /  x

           x c  =  (a b² / c)

           x     =  a b² / c²  men   . 

Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it.  That's the answer I got, and I'm stickin to it.
Rrarrup !  
8 0
3 years ago
Algebraically find the inverse of a function​
Savatey [412]

9514 1404 393

Answer:

  1)  f⁻¹(x) = 6 ± 2√(x -1)

  3)  y = (x +4)² -2

  5)  y = (x -4)³ -4

Step-by-step explanation:

In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.

__

1) x = f(y)

  x = (1/4)(y -6)² +1

  4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4

  ±2√(x -1) = y -6 . . . . square root

  y = 6 ± 2√(x -1) . . . . inverse relation

  f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form

__

3) x = √(y +2) -4

  x +4 = √(y +2) . . . . add 4

  (x +4)² = y +2 . . . . square both sides

  y = (x +4)² -2 . . . . . subtract 2

__

5) x = ∛(y +4) +4

  x -4 = ∛(y +4) . . . . . subtract 4

  (x -4)³ = y +4 . . . . . cube both sides

  y = (x -4)³ -4 . . . . . . subtract 4

6 0
3 years ago
Identify the corresponding parts.
zheka24 [161]

Answer:

S,Z,F

Step-by-step explanation:

i just did it

4 0
3 years ago
Mg+rg=2H, solve for g
lesantik [10]

Answer:

g = 2H/(m + r)

Step-by-step explanation:

mg + rg = 2H

g(m + r) = 2H

(g(m + r))/(m + r) = 2H/(m + r)

g = 2H/(m + r)

3 0
3 years ago
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