MV is the answer. Because AC to VJ as RO is just MV
Scale factor is 2
30/15 = 2
20/10 = 2
Answer:
The equation of the circle is
Formula :
(x- h ) ² + (y-k )² = r²
or, x²-20x +100 + y² -8y + 16 = 16
or, x² + y² -20x -8y + 100 = 0 is the required equation
Answer:
x intercepts at (-3,0), and (1,0)
there is a minimum at (-1,-4)
Step-by-step explanation:
Please see attached image for the requested graph of the function
, and observe that the crossings of the x-axis are at the points (-3,0), and (1,0) , marked in red in the image.
We can also see that there is no maximum, but a minimum value, and located at the point (-1,-4) [marked in green in the image]
Answer:
E) we will use t- distribution because is un-known,n<30
the confidence interval is (0.0338,0.0392)
Step-by-step explanation:
<u>Step:-1</u>
Given sample size is n = 23<30 mortgage institutions
The mean interest rate 'x' = 0.0365
The standard deviation 'S' = 0.0046
the degree of freedom = n-1 = 23-1=22
99% of confidence intervals
(from tabulated value).
![The mean value = 0.0365](https://tex.z-dn.net/?f=The%20mean%20value%20%3D%200.0365)
![x±t_{0.01} \frac{S}{\sqrt{n-1} }](https://tex.z-dn.net/?f=x%C2%B1t_%7B0.01%7D%20%5Cfrac%7BS%7D%7B%5Csqrt%7Bn-1%7D%20%7D)
![0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }](https://tex.z-dn.net/?f=0.0365%C2%B12.82%20%5Cfrac%7B0.0046%7D%7B%5Csqrt%7B23-1%7D%20%7D)
![0.0365±2.82 \frac{0.0046}{\sqrt{22} }](https://tex.z-dn.net/?f=0.0365%C2%B12.82%20%5Cfrac%7B0.0046%7D%7B%5Csqrt%7B22%7D%20%7D)
![0.0365±2.82 \frac{0.0046}{4.690 }](https://tex.z-dn.net/?f=0.0365%C2%B12.82%20%5Cfrac%7B0.0046%7D%7B4.690%20%7D)
using calculator
![0.0365±0.00276](https://tex.z-dn.net/?f=0.0365%C2%B10.00276)
Confidence interval is
![(0.0365-0.00276,0.0365+0.00276)](https://tex.z-dn.net/?f=%280.0365-0.00276%2C0.0365%2B0.00276%29)
![(0.0338,0.0392)](https://tex.z-dn.net/?f=%280.0338%2C0.0392%29)
the mean value is lies between in this confidence interval
(0.0338,0.0392).
<u>Answer:-</u>
<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>