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lisabon 2012 [21]

2 years ago

7

The whole cost of a bicycle is 98.75 the market for the bicycle is 33.3% of the selling price of the bicycle to the nearest cebt

2 answers:

Maslowich2 years ago

7 0

Answer:

$131.60

Step-by-step explanation:

Naya [18.7K]2 years ago

4 0

Answer:

$131.60

Step-by-step explanation:

Selling Price = $98.75 + $98.75*33.3%

Selling Price = $98.75 + $32.88375

Selling Price = $131.63375

Selling Price = $131.60

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The price of a computer was decreased by 7% to £500. What was the price before the decrease? Give your answer to the nearest pen

aliina [53]

Answer:

537.6

Step-by-step explanation:

0.93*x=500

x=500/0.93

x=537.6

8 0

2 years ago

The sum of three numbers is 7. One of the numbers is one more than the sum of the other two numbers. It is also four times the d

Sedaia [141]

The only numbers I could think of would be 1, 2, and 4 because 4 is greater than 3 (2+1) and four times greater than 1 (2-1)

5 0

3 years ago

Read 2 more answers

A bookkeeper bought 2,000 exercise book distributed 200 books to the student from poor economic background as donation .he sold

Andrews [41]

Books left=2000-200=1800

ATQ

$\\ \sf\longmapsto 1800x+10=0.08x$

$\\ \sf\longmapsto 1800x-0.08x=-10$

$\\ \sf\longmapsto x(1800-0.08)=-10$

$\\ \sf\longmapsto x(1799.92)=-10$

$\\ \sf\longmapsto x=|\dfrac{10}{1799.92}|$

$\\ \sf\longmapsto x=0.005$

Now

$\\ \sf\longmapsto CP=0.005(2000)=10$

6 0

2 years ago

One can convert temperature from Fahrenheit into Newton using the formula N=11/60(F-32) . What is the temperature in Fahrenheit

Rasek [7]

We are given

$N=\frac{11}{60} (F-32)$

Since, we have to solve for F

so, we will isolate F on anyone side

step-1:

Multiply both sides by 60

$60\times N=60\times \frac{11}{60} (F-32)$

$60N=11 (F-32)$

step-2:

Divide both sides by 11

$\frac{60N}{11} =\frac{11(F-32)}{11}$

$\frac{60}{11}N =F-32$

step-3:

Add both sides by 32

$\frac{60}{11}N+32 =F-32+32$

$\frac{60}{11}N+32 =F$

so, we get

$F=\frac{60}{11}N+32$ ................Answer

5 0

2 years ago

Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required

xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

$A = Pe^{rt}$

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

A = 2 × $3000

A = $6000

$6000 = 3000e^{0.085t}$

$\frac{6000}{3000} = e^{0.085t}$

$2 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}2 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln2 = 0.085t$

$t = \frac{ln2}{0.085}$

$t = \frac{0.693}{0.085}$

t = 8.15

(b) For the amount to double, A = 3 × P

A = 3 × $3000

A = $9000

$9000 = 3000e^{0.085t}$

$\frac{9000}{3000} = e^{0.085t}$

$3 = e^{0.085t}$

Take $log_{e}$ of both sides

$log_{e}3 = log_{e}e^{0.085t}$

But $log_{e}e = 1$

∴ $ln3 = 0.085t$

$t = \frac{ln3}{0.085}$

$t = \frac{1.0986}{0.085}$

t = 12.92

5 0

3 years ago