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lorasvet [3.4K]
3 years ago
13

24 is 40% of what number

Mathematics
2 answers:
sattari [20]3 years ago
8 0
24 is 40% of 60
first you do 24/4=6  and 40%/4=10%
then 6*10=60 and 10%*10=100%
*=times
tatiyna3 years ago
5 0
60 is the answer ....hope it helped
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Can someone help me please
MAXImum [283]
13. 12 3/8
14. 9 2/3
15. 3 4/10
16. 3
6 0
3 years ago
Thank you for the help guys! <br><br> Find m ABC
Akimi4 [234]
Vertical angles are equal

7x - 19 = 4x + 2
7x - 4x = 2 + 19
3x = 21
x = 21/3
x = 7

m∠ABC = 4x + 2 = 4*7 + 2 = 28 + 2 = 30°
4 0
3 years ago
What is the surface area of a rectangular prism that has a height of 5 cm, a width of 10 cm, and a depth of 4 cm?
Ket [755]

Option C: 220 \ cm^2 is the surface area of the rectangular prism

Explanation:

The height of the rectangular prism is 5 cm

The width of the rectangular prism is 10 cm

The depth of the rectangular prism is 4 cm

We need to determine the surface area of the rectangular prism.

The surface area of the rectangular prism can be determined using the formula,

A=2(w l+h l+h w)

Substituting w=10 , h=5 and l=4 in the formula, we get,

A=2 \cdot(10 \cdot 4+5 \cdot 4+5 \cdot 10)

Multiplying the terms within the bracket, we have,

A=2 \cdot(40 +20+5 0)

Adding all the values within the bracket, we get,

A=2 \cdot(110)

Multiplying, we have,

A=220

Thus, the surface area of the rectangular prism is 220 \ cm^2

Hence, Option C is the correct answer.

4 0
3 years ago
Read 2 more answers
Simplify completely 12 times x to the third power minus 4 times x to the 2nd power plus 8 times x all over negative 2 times x.
Alenkinab [10]
The answer is: -6x^2+2x-4
5 0
3 years ago
Plz give explanation.<br> solve | k-10 | = 3
Ne4ueva [31]

Answer:

13

Step-by-step explanation:

Explanation:

Use the absolute value definition to rewrite the absolute value equation as two separate equations.

k-10=3

k-10=-3

Solve the equation for k

k=13

k-10=-3

k=13

k=7

The equation has 2 solutions, meaning k1=7,k2=13. Which gives you the answer of: 13 (K1=7,k2=13)

6 0
2 years ago
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