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Nutka1998 [239]

3 years ago

6

How do you solve this absolute value equation? ∣x−2∣=∣4+x∣

1 answer:

snow_tiger [21]3 years ago

6 0

L x - 2 l = l 4 + x l

Remember : Absolute is just the distance from zero.

Ex : l -4 l turns into 4, as it is 4 spaces away from zero on a number line :)

l x - 2 l turns into x + 2

l 4 + x l stays the same.

So, our equation now looks like this :

x + 2 = 4 + x

So, we're basically just trying to get x by itself.

So, subtract 2 from both sides.

x = 4 + x - 2

Then, subtract x from both sides.

x - x = 4 -2

0 = 2

Therefore, there are no solutions to this equation :)

~Hope I helped!~

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melisa1 [442]

The number of days it will take to consume the given power = 4.5 days

<h3>Calculation of energy consumption</h3>

The amount of power consumed per day = 1440watt-hours

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Make X the subject formula;

X = 1 × 6480/1440

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2 years ago

A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

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3 years ago

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zepelin [54]

Answer:

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Step-by-step explanation:

you can't have the square root of a negative number

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