Answer:
.15 * 60 = 9
$9
Step-by-step explanation:
Start at the point (2, -3) and then go up 3 and to the right 4 a few points and then go down 3 and to the left 4 a few points and then from there you can get an equation out of it
The answer is

To figure this out, convert both numbers to fractions. 1.03 = 1

and (-10.3) = -10

. Now, convert to improper fractions.
1
![\frac{3}{100} = [tex] \frac{103}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B100%7D%20%20%3D%20%5Btex%5D%20%5Cfrac%7B103%7D%7B100%7D%20)
-10

=

Now, divide. Dividing fractions is the same as multiplying by the reciporical. So:

Answer:
8*8*8= <em><u>8^3= 512</u></em>
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have to make 5 place serial number with first two as alphabets and last three as digits.
The alphabets are bonded to first 6 ( A, B, C, D, E, F) where as digits are 10 (say 1 to 10).
Let the serial number be S1 S2 S3 S4 S5.
For Alphabets
For S1 we have 6 alphabets.
Now for S2 we are left with 5 alphabets since there is no repetition one alphabet will be fix for S1.
So the possible combination for S1 S2= 6x5=30.
For Digits
We did the same as we did for alphabets, for S3 we have 10 possibilities, and for S4 and S5 9 and 8 respectively due to the no repetition condition.
So the possible combinations for S3 S4 S5 = 10x9x8=720
So the total number of serial numbers are 30+720=750.