Roll two fair dice separately. Each die has six faces. a. List the sample space. b. Let A be the event that either a three or fo
1 answer:
Answer:
Step-by-step explanation:
a) {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}
=6*6=36
b)A=(2*3)=6
P(A)=6/36=1/6
c) B=6+5+4+3+2+1=21
P(B)=21/36
d) P(A|B) - an event where either a 3 or 4 is rolled first and is followed by an even number and their sum goes over 7
P(A|B)=3
e) Not always, not sure how to explain, I'm not good with English Math
f) Same as above
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Answer:
Conclusion
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.
(D) P-val=0.021, fail to reject the null hypothesis
Step-by-step explanation:
1) Data given and notation
represent the mean for the temperatures
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is less than 22C, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
We can calculate the degrees of freedom like this:
Since is a one left tailed test the p value would be:
Conclusion
If we compare the p value and the significance level given we see that
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.
The best option would be:
(D) P-val=0.021, fail to reject the null hypothesis
Answer:
50 yellow marbles.
Step-by-step explanation:
Information:
170 marbles
RED : BLUE : YELLOW
9 : 3 : 5
Solving:
To find out how many yellow parts there are, we need to find out how many marbles 5 parts account to.
Altogether, 9 + 3 + 5 = 17. This means there are 17 parts.
The bag contains 170 marbles and the ratio adds up to 17 parts.
We can figure out what 1 part of the ratio accounts to by dividing 170 by 17.
= 10.
1 part = 10
Now remember yellow is 5 parts, now that we know that 1 part is 10, we need to multiply 10 by 5 to find out how many yellow marbles we have.
5 x 10 = 50.
Therefore we have 50 yellow marbles.