Answer:
Step-by-step explanation:
a) {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}
=6*6=36
b)A=(2*3)=6
P(A)=6/36=1/6
c) B=6+5+4+3+2+1=21
P(B)=21/36
d) P(A|B) - an event where either a 3 or 4 is rolled first and is followed by an even number and their sum goes over 7
P(A|B)=3
e) Not always, not sure how to explain, I'm not good with English Math
f) Same as above