I think the answer is 2.8
Answer:
3.9 mi/h
Step-by-step explanation:
If the boy is rowing perpendicular to the current, the two vectors form a right triangle.
AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat
AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37
AC = sqrt(15.37) = 3.9 mi/h
The boat's speed over the ground is 3.9 mi/h.
Angles XQL and MQR are congruent because they are vertical angles. So
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
Solve for <em>b</em> :
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
209 - 146 = 13 <em>b</em> - 4<em> b</em>
63 = 9 <em>b</em>
<em>b</em> = 63/9 = 7
Then the measure of angle XQL is
(209 - 13*7)º = 118º
Answer:
4,5,6
Step-by-step explanation:
*The sign of ≥ means that it must be greater or equal to 10 in this case
1). 3 isn't a possible solution due to 9 being less than 10
3+6_10
9_10
9<10
2). 4 is a possible solution due to the sum of 4 and 6 being equal to 10
4+6_10
10_10
10=10
3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10
5+6_10
11_10
11>10
4).6 is a possible solution due to the sum of 6 and 6 being larger than 10
6+6_10
12_10
12>10
Hope this helped! (:
Answer: B. 2x + 2 + x
Step-by-step explanation:
I took the quiz.
