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Olin [163]
3 years ago
11

Rosy has 16 pencils and 24 erasers. She is putting together packets that will have an equal number of pencils and erasers in eac

h packet. If Rosy uses all of the pencils and erasers, what the the maximum number of packets she can make?
Mathematics
2 answers:
Effectus [21]3 years ago
8 0

Answer:

If she puts 2 pencils and 3 erasers in each packet,

Rosy can make a total of 8 packets.

tia_tia [17]3 years ago
6 0

Answer:

the max packets she can make is 8

Step-by-step explanation:

16/8=2 and 24/8=3 s and if she make more packets there will be a decimal amount of erasers.

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Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

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