4 adult tickets were sold and 8 student tickets were sold.
How did I get this?
First, let's see what information is given:
12 tickets sold
(S)tudent ticket = $9
(A)dult ticket = $12
Total cost = $120
So, we know student tickets plus adult tickets total up to $12. We can create an equation out of this: S + A = 12
And we know $9S + $12A = $120
The variables represent the amount of tickets sold, which is unknown.
A = 12 - S , substitute this into the second equation.
9s + 12(12-s) = 120
Distribute the 12 into the parenthesis.
9s + 144 - 12s = 120
Combine like terms
-3s + 144 = 120
Subtract both sides by 144, left side cancels out.
-3s = -24
s = -24/-3
s = 8
So, 8 student tickets were sold. Plug the value of s into our first equation.
A = 12 - 8
A = 4 (adult tickets)
Answer:
The question gives you V0 as 220, so plug that in first.
h=-16t2+220t.
Then it says to find the time (solve for t), when the height is 400 ft. Plug 500 ft in as h and solve for t.
500=-16t2+220t.
To solve this, set the quadratic equal to 0 by subtracting 500 from both sides (0=-16t2+220t-500) and use the quadratic formula!
Step-by-step explanation:
9514 1404 393
Answer:
A, C
Step-by-step explanation:
The values listed (least-to-greatest) are ...
{-5, -2, 0, 2}
All of these values are integers.
Not all of these values are between -4 and 2. (-5 is outside that range)
All of these values are less than 5.
__
The true statements are A and C.
