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3 years ago

Combine the like terms to create an equivalent expression. 7x−x

Mathematics

1 answer:

Alina [70]3 years ago

3 0

Hello from MrBillDoesMath!

Answer:

Discussion:

7x = 7 times x

x = 1 times x

So both terms are "like" terms in x:

7x - x = (7-1)x = 6x

Thank you,

MrB

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The perfect orange calls for 2/3 parts yellow paint and 1/4 parts red paint.

sergejj [24]

A. 2 2/3

B. 3/8

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4 years ago

Will the graph of the line represented by the table x-1,0,1,2 y-1,3,7,11 intersect the graph of y=4x+5 explain

Nadusha1986 [10]

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3 years ago

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What is the simplest form of this expression w^2(-4w^2-2)+(-5w^2)(-2w^2-2)

VikaD [51]

Answer:
6w⁴ + 8w²

Explanation:
Before we begin, remember the following:
xᵃ * xᵇ = x⁺ᵇ
+ve * -ve = -ve
-ve * -ve = +ve
+ve * +ve = +ve

To solve this problem, we will follow the following steps:
1- get rid of the brackets using the distributive property
2- combine like terms

This can be shown as follows:
w²(-4w² - 2) + (-5w²)(-2w² - 2)
w²(-4w²) + w²(-2) + (-5w²)(-2w²) + (-5w²)(-2)
-4w⁴ - 2w² + 10w⁴ + 10w²
w⁴(-4+10) + w²(-2+10)
6w⁴ + 8w²

Hope this helps :)

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3 years ago

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A, B, and C are points on the circumference of a circle, centre 0. AOB is a diameter of the circle. Prove that angle ACB is 90°

ki77a [65]

Answer:

Kindly refer to explanation.

Step-by-step explanation:

Given that:

A,B and C are 3 points on circumference of circle with centre O.

AOB is diameter.

Kindly refer to the attached image.

To prove:

$\angle ACB = 90^\circ$

Solution:

Let $\angle A = x$ and $\angle B = y$ .

<em>Construction</em>: Join point A with centre O.

Considering $\triangle AOC$ :

Side AO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, $\angle ACO=\angle A=x$

Considering $\triangle BOC$ :

Side BO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, $\angle BCO=\angle B=y$

$\angle ACB = \angle ACO + \angle BCO = x+y$ ...... (1)

Now, in $\triangle ABC:$

Using angle sum property of triangle:

$\angle A + \angle B + \angle ACB =180^\circ\\\Rightarrow x+y+x+y=180^\circ\\\Rightarrow 2(x+y)=180^\circ\\\Rightarrow x+y=90^\circ$

By equation (1):

$\angle ACB = 90^\circ$

Hence proved.

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3 years ago

.........<br> ........<br> ........

kumpel [21]

Answer:

1 yellow would be 1/4, 2 red would be 1/8, 3 blue would be 1/4, and 4 green would be 3/8. please mark me brainliest by perssing or clicking the crown it would help me out.

Step-by-step explanation:

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3 years ago