If you mean unit rate you find it by dividing the top number by the bottom number to fin the singular number or unit rate.
The equivalent expression for [gofoh](9) is 5(32(9)^5-1).
According to the given question.
We have three functions
f(x) = x^5 - 1
g(x) = 5x^2
h(x) = 2x
Here, we have to find the equivalent expression for [gofoh](9).
so,
gofoh(x)
= g((2x)^5 -1)
= g(32x^5 -1)
= 5(32x^5 -1)
Therefore,
gofoh(9)
= 5(32(9)^5-1)
Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).
Find out more information about equiavlent expression here:
brainly.com/question/28170201
#SPJ4
Answer:
C(t)=5000 -10t
Step-by-step explanation:
There are many examples in the real world of relationships that are functions.
For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.
If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:

Where:
C (t): Amount of water in the tank as a function of time
: Initial amount of water in the tank at time t = 0
a: amount of water lost per hour
t: time in hours
Then the equation is:
The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.
Its domain is the set of all positive real numbers t between [0,500]
Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty
Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres
Answer:
38.46 (Rounded: 38.5)
Step-by-step explanation:
67.32-2(14.43)=38.46
Answer:
6y(y^2-3x)
Step-by-step explanation:
6y^3-18xy=6y(y^2-3x)