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Anuta_ua [19.1K]
3 years ago
7

Airborne mercury has received special attention because it is a widespread and persistent neurotoxin (a substance that damages t

he brain and nervous system). minute doses can cause nerve damage and other impairments, especially in young children and developing fetuses. the majority of airborne mercury is released by __________.\
Biology
1 answer:
notka56 [123]3 years ago
5 0
The answer to this question is the "coal-burning power or the power plants". Hence, the Airborne mercury has received special attention because it is a widespread and persistent neurotoxin. TA neurotoxin is a substance that damages the brain and the nervous systems. Minute doses can cause nerve damage and other impairments, especially in the young children and the developing fetuses. The majority of the airborne mercury is released by POWER PLANTS or coal-burning plants. Many people are affected and get sick that is why when there is a proposed new power plant project, most people object and opposed.
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What difference do you observe between animal and plant cells?
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cell wall

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Animal cells do not have a cell wall

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18. Refraction is caused by
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Explanation:

Option D is the correct option.

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Classify each statement based on whether it describes prokaryotes only, eukaryotes only, or can describe both prokaryotes and eu
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Answer:

unicellular - both prokaryotes and eukaryotes

contain mitochondrion - eukaryotes only

are generally less than 2 pm - Prokaryotes only

multicellular - eukaryotes only

lack membrane-bound organelles - prokaryotes only

Explanation:

Prokaryotes are generally unicellular, that is, they are made up of single cells only. However, there are unicellular and multicellular eukaryotes with some eukaryotes like humans and advanced plants having as many as millions of cells.

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7 0
3 years ago
A population of 100 tigers has 30 with horizontal stripes. Using pedigrees, you ascertain that horizontal striping is caused by
bixtya [17]

Assuming that this population is in Hardy-Weinberg equilibrium, we can sayt that  <em>the</em><em> probability</em><em> that, given enough time, all tigers in the population will have horizontal stripes is</em><em> 30% = 0.3.</em>

--------------------------

<u>Available data:</u>

  • Population size, N = 100 tigers
  • Number of Tigers with horizontal stripes = 30
  • Horizontal stripes is caused by an autosomal recessive mutation.

We need to know the probability that all tigers in the population will have horizontal stripes, which is the recessive phenotype.

We assume that the population is in Hardy-Weinberg equilibrium, so there should be no evolution.

Since the population is in H-W equilibrium, the allelic, genotypic and phenotypic frequencies will remain the same generation after generation.

Now, we will calculate the allelic and genotypic frequencies of horizontal striped individuals in the population.

There are 100 individuals, and only 30 have horizontal stripes.

So, the phenotypic frequency, F(HS) is 30/100 = 0.3 = 30%

Since this is a recessive phenotype, this value equals the genotypic frequency, F(hh) = 30%

Finally, we can get the allelic frequency by taking the square root of this value.

F(hh) = q² = 0.3

f(h) = q = √0.3 = 0.55 = 55%

According to these calcs, the probability for the fixation of the recessive allele is 55%, and the probability that all individuals express the recessive horizontal stripes phenotype is 30%.

--------------------------

You can learn more about Hardy-Weinberg equilibrium at

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