Andy is wrong.
3/5 = 12/20
1/4 = 5/20
Add them up
12/20 + 5/20 = 17/20
17/20 is not equal to 4/9
Answer:
The answer to your question is 43.8 mL of acid.
Step-by-step explanation:
Data
Total volume = 362 ml
12.1 % is acid
The Volume of acid = ?
Process
1.- Use the rule of three and cross multiplication to solve this problem.
362 ml ------------------- 100%
x ------------------- 12.1 %
x = (12.1 x 362) / 100
x = 4380.2 / 100
x = 43.802 ml
2.- Round your answer to the nearest tenth.
43.802 only consider the first decimal
43.8 mL
3.- Conclusion
A 12.1% solution of acid has 43.8 mL of acid.
9514 1404 393
Answer:
$2.98
Step-by-step explanation:
The amount of interest earned is ...
I = P((1 +r)^t -1)
I = $9(1.1^3 -1) ≈ $2.98
Daniel will earn about $2.98 in interest in 3 years.
This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.
There aren't any parallel lines involved in the above described construction, so I'll skip the first one.
2. Why do the circles have to be congruent ...
The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.
3. ... circles of different sizes ...
[We just answered that. Let's do it again.]
Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.
4. ... construct the perpendicular bisector ... a different way?
Maybe what I first described is different; there are no parallel lines.
