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Sergeu [11.5K]
2 years ago
7

Which ordered pair is a solution to the system of inequalities graphed here?

Mathematics
1 answer:
saul85 [17]2 years ago
6 0

Answer: I dont know

Step-by-step explanation:

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What is 3/5 times 6/5
Angelina_Jolie [31]

Answer is 0:72

hope it is helpful

6 0
3 years ago
Read 2 more answers
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
How do you find how many times larger
masya89 [10]

Answer

whats the problem.

Step-by-step explanation:

 

4 0
3 years ago
Solve the variable in the following proportion. 3.6/y=1.2/2
Molodets [167]
Hello : 
<span>3.6/y=1.2/2
1.2 y = 2(3.6)
y = 2(3.6)/1.2
y=6</span>
7 0
3 years ago
Assume that the weight of two year old babies have distribution that is approximately normal with a mean of 29 pounds and a stan
Lana71 [14]

Answer:

25.15 ponds is the weight of two year old baby corresponds to 10th percentile.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 29 pounds

Standard Deviation, σ = 3 pounds

We are given that the distribution of weight of two year old babies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.10

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 29}{3})=0.10  

Calculation the value from standard normal z table, we have,  

P(z < -1.282) = 0.10

\displaystyle\dfrac{x - 29}{3} = -1.282\\x = 25.154 \approx 25.15

Thus, 25.15 ponds is the weight of two year old baby corresponds to 10th percentile.

5 0
3 years ago
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