In this item, we are to determine the number of high fives given considering that there are 12 total number of participants in the meeting. We know for a fact that each high five will require 2 participants. We can determine the answer to this item by using the concept of Combination.
Combination of 12 taken 2 can be expressed as 12C2 and can be solved using the equation,
n = (12!)/(2!)(12 - 2)!
This expression is equal to 66. Hence, the answer to this item is 66 high fives.
Answer:
Disclaimer: There is error in the Q. In (II) there should have been 2x - 3y = 12
5x + 3y = 9 -----(I)
2x - 3y = 12 ----- (II)
Add (I) and (II)
7x = 21
x = 3
Putting the value of x = 3 in (I) we get
5(3)+3y=9⇒15+3y=9⇒3y=9-15=-6⇒y=-2
Thus, (x, y) = (3, -6).
Step-by-step explanation:
Answer:
D) 3x
Step-by-step explanation:
The difference of adjacent terms is ...
(-7x) -(-10x) = (-7+10)x = 3x . . . . the common difference
Answer : -9/10
-4/5 times 9/8 = -36/40
Then simplify that you get -9/10