Question

the length of a rectangle is 1 yards more than twice the width and the area of a rectangle is 28-yard square find the dimension of the rectangle

Answer 1

Assuming you mean the area is 28 yd², equations for the length (y) and width (x) can be written:

$y=1+2x\\xy=28$

These equations can be solved by a variety of means. One I like is graphing. A graphing calculator tells you the solution is (width, length) = (3.5 yd, 8 yd).