Question

A 55-inch television screen has a shape of a rectangle with a diagonal that is 55 inches long and a width of the screen is 27 inches.
What is the perimeter of the screen?



Enter your answer, rounded to the nearest hundredth, in the box.


in.

Answer 1

 L^2 = 55^2 - 27^2

L^2 = 3025 - 729
 L^2 = 2296
L = sqrt(2296) = 47.92 inches

 perimeter = 27*2 + 47.92*2 = 54 + 95.84 = 149.84 inches

Answer 2

Answer:

Perimeter of the rectangle = 149.84 inches.

Step-by-step explanation:

Given : A 55-inch television screen has a shape of a rectangle with a diagonal that is 55 inches long and a width of the screen is 27 inches.

To find : What is the perimeter of the screen?

Solution :

Diagonal of the rectangular screen is D=55 inches

The width of the screen is W= 27 inches

Rectangle all angles are of 90°

Apply Pythagorean theorem,

$D^2=L^2+W^2$

$55^2=L^2+27^2$

$L^2 = 55^2 - 27^2$

$L^2 = 3025 -729$

$L^2 = 2296$

$L = \sqrt{2296}$

$L= 47.92 in.$

Length L=47.92

Perimeter of the rectangle = 2(L+W)

Perimeter of the rectangle = 2(47.92+27)

Perimeter of the rectangle = 2(74.92)

Perimeter of the rectangle = 149.84 inches.