Question

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Answer 1

Here is how I completed the problem:

I started by creating a ratio:

$\frac{x}{0.18} + \frac{360}{0.10} = \frac{x+360}{0.15}$

Where 'x' is the desired amount of the 18% solution of sulfuric acid. 

From here, I solved for 'x':

$\frac{0.10x}{0.018} + \frac{360(0.18)}{0.018} = \frac{x+360}{0.15}$
$\frac{0.10x}{0.018} + \frac{64.8}{0.018} = \frac{x+360}{0.15}$
$\frac{0.10x+64.8}{0.018} = \frac{x+360}{0.15}$
$0.15(0.10x+64.8) = 0.018(x+360)$
$0.015x+9.72 = 0.018x+6.48$
$0.003x = 3.24$
$x = 1080$

∴You will need to add 1080ml of 18% Sulfuric Acid in order to obtain a 15% solution.