Question

Find the quotient. 12 a3 p4 ÷ -2a2p

Answer 1

Answer: $-6ap^3$

Step-by-step explanation:

Here the given expression is,

$\frac{12a^3p^4}{-2a^2p}$

= $\frac{-12\times a^3\times a^{-2}\times p^4\times p^{-1}}{2}$        $( \frac{1}{a^x} = a^{-x} )$

= $-6\times a^{3-2}\times p^{4-1}$  $( a^m\times a^n = a^{m+n} )$

= $-6 \times a^1\times p^3$

= $-6ap^3$

Answer 2

Answer:

-6a / p³

Step-by-step explanation:

Given expression is

$12a^{3} p^{4} /(-2a^{2}p)$

We have to simplify above expression.

We use two formulas in this expression.

xⁿ = 1/x⁻ⁿ        (formula 1)

$x^{m}$×$x^{n}$ = $x^{m+n}$         ( formula 2)

using (formula 1) in given expression,we get

$12 a^{3} p^{4} a^{-2} p^{-1} /-2$

using (formula 2 ) in above expression ,we get

$12a^{3-2} p^{4-1} /-2$

12a¹p⁻³ / -2

2×6ap⁻³ / -2

-6a / p³ which is the answer.