Find the quotient. 12 a3 p4 ÷ -2a2p
2 answers:
Answer: ![-6ap^3](https://tex.z-dn.net/?f=-6ap%5E3)
Step-by-step explanation:
Here the given expression is,
![\frac{12a^3p^4}{-2a^2p}](https://tex.z-dn.net/?f=%5Cfrac%7B12a%5E3p%5E4%7D%7B-2a%5E2p%7D)
=
![( \frac{1}{a^x} = a^{-x} )](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7Ba%5Ex%7D%20%3D%20a%5E%7B-x%7D%20%29)
=
![( a^m\times a^n = a^{m+n} )](https://tex.z-dn.net/?f=%28%20a%5Em%5Ctimes%20a%5En%20%3D%20a%5E%7Bm%2Bn%7D%20%29)
= ![-6 \times a^1\times p^3](https://tex.z-dn.net/?f=-6%20%5Ctimes%20a%5E1%5Ctimes%20p%5E3)
= ![-6ap^3](https://tex.z-dn.net/?f=-6ap%5E3)
Answer:
-6a / p³
Step-by-step explanation:
Given expression is
![12a^{3} p^{4} /(-2a^{2}p)](https://tex.z-dn.net/?f=12a%5E%7B3%7D%20p%5E%7B4%7D%20%2F%28-2a%5E%7B2%7Dp%29)
We have to simplify above expression.
We use two formulas in this expression.
xⁿ = 1/x⁻ⁿ (formula 1)
×
=
( formula 2)
using (formula 1) in given expression,we get
![12 a^{3} p^{4} a^{-2} p^{-1} /-2](https://tex.z-dn.net/?f=12%20a%5E%7B3%7D%20p%5E%7B4%7D%20a%5E%7B-2%7D%20p%5E%7B-1%7D%20%2F-2)
using (formula 2 ) in above expression ,we get
![12a^{3-2} p^{4-1} /-2](https://tex.z-dn.net/?f=12a%5E%7B3-2%7D%20p%5E%7B4-1%7D%20%2F-2)
12a¹p⁻³ / -2
2×6ap⁻³ / -2
-6a / p³ which is the answer.
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Step-by-step explanation:
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Answer:
I don't know this but please ask the tutors on brainly hope this helps!!!