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Sphinxa [80]
3 years ago
12

-4x+3y=-2y=x-1y=? x=?​

Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

x=-1 , y=-2

Step-by-step explanation:

Replace y in the first equation with x-1.

So, we have -4x+3(x-1)=-2

Multiply brackets with 3: -4x+3x-3=-2

-4x+3x=-2+3 (-3 becomes +3 after it changes sides)

-x=1 /*(-1)

x=-1

After we have x we include it in y=x-1

y=-1-1

y=-2

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ATCE Learning Center wants to make a net profit of $650,000 on the manual it sells to schools. The fixed costs for producing the
Elanso [62]
We are to solve for the price per unit. Let "x" be the price per unit.
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6 0
2 years ago
PLLEASE ANSWER THIS FOR ME
stiv31 [10]

Answer:

<h2>120 square meters</h2>

Step-by-step explanation:

To find the SA of 2 Triangles, we will use the formula... B x H, and the Base and Height is going to be the dimensions of just 1 triangle, but it's going to give the answer for 2 triangles, in this shape, we have 2 triangles.

SA = B x H

= 6 x 4

= 24

24 square meters for both of the triangles

Now, let's find the SA of the rectangle on the bottom...

SA = L x W

= 6 x 6

= 36

36 square meters for 1 of the 3 rectangular parts, the one on the bottom

Now, lets find the SA of the 2 rectangles on the top. We'll use the dimensions of 1 rectangle and find the answer for 2 answers by using the formula...

SA = L x W x 2

= 6 x 5 x 2

= 30 x 2

= 60

60 square meters for the 2 rectangles on the top.

Now, we have to add all of our answers.

24 + 36 + 60 = 120 square meters

<h2>Hence, the SA (surface area) of this shape is 120 square meters.</h2>

~Brainly Master - Helping Students~

4 0
2 years ago
A stadium has a a central rectangular area 125m long by 80m wide.there are two semi circular ends.a running track goes all the w
Fudgin [204]

a)The total inside length of the curved ends of the track will be 25.13 meters

b)The total distance around the inside of the track will be 275.13 meters

c)The area inside the track is 10050 square meters.

<h3>What is an area?</h3>

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

A stadium has a central rectangular area 125m long by 80m wide. there are two semi-circular ends. a running track goes all the way around.

a) what is the total inside length of the curved ends of the track?

The length of the curved track means it is a perimeter of the circle so the radius of the semicircle will be 4 meters.

So the length will be = π r + πr = 2 πr

                                  = 2 x π x 4 = 25.13

b) what is the total distance around the inside of the track?

The total distance of the track will be the sum of the length of the two semicircles and the longer side of the rectangle.

Total length = 125 + 125 + 25.13

                     = 275.13 meters

c) what is the area inside of the track?

The area will be equal to the area of the two semicircular tracks and the rectangular track.

Total Area = Area of semicircle + Area of semicircle + Area of rectangle

                  = ( π/2 ) r² + (π/2) r² + ( L x W )

                  =  π  r² + (  L x W)

                  = π ( 4 )² + ( 125 x 8 )

                  = 10050.26 square meters.

Therefore the total inside length of the curved ends of the track will be 25.13 meters. The total distance around the inside of the track will be 275.13 meters. The area inside the track is 10050 square meters.

To know more about an area follow

brainly.com/question/25292087

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3 0
1 year ago
Simplify 3^5/3^2.<br> I do have a basic understanding but I need help on this.
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Given that "a" and "b" are positive integers; and that "x" is a real number greater than "zero"; 
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xᵃ /xᵇ = x⁽ᵇ ⁻ ᵃ⁾
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7 0
3 years ago
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