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Pie
3 years ago
10

How to find the average squared distance between the points of the unit disk and the point (1,1)

Mathematics
1 answer:
ddd [48]3 years ago
5 0
The unit disk can be parameterized by the function

\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)

where 0\le r\le 1 and 0\le\theta\le2\pi. The squared distance between any point in this region (x,y)=(r\cos\theta,r\sin\theta) and the point (1, 1) is

(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2
=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)
=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2
=r^2-2r(\cos\theta-\sin\theta)+2

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

\dfrac{\displaystyle\iint_{x^2+y^2
=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}
=\dfrac{\frac{5\pi}2}\pi=\dfrac52
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the family fine arts center charges $24 per adult and $12 per senior citizen for its performances. on a recent weekend evening w
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337 were senior citizens.

What is the system of equations?

A system of equations, also known as an equation system or a set of simultaneous equations, is a finite set of equations for which common solutions are sought.

Here, we

Let

x = the number of adult tickets sold

y = the number of senior tickets sold

483 people paid admission => a total of 483 tickets were sold and

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the total receipts were $7548

24x + 12y = 7548

by solving the system of equations

x + y = 483....(1)

24x + 12y = 7548....(2)

From equation (1), we get

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Now, we put the value of x in equation (2) and we get

24(483 - y) +12y = 7548

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Hence, 337 were senior citizens.

To learn more about the system of equations from the given link

brainly.com/question/25976025

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7 0
1 year ago
HELP PLZZZ ASAP!!!!!
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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

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13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

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Here are the 4 numbers that satisfy both event A and event B:

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