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3 years ago

Pls explain your answer

Mathematics

1 answer:

jasenka [17]3 years ago

7 0

Middle square area= 8x8=64
one triangle area = (8x8)/2
multiply the triangel area by four and add the square area-- (4x32)+64=192

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Half a pepperoni pizza plus three fourths of a ham and pineapple pizza contains 765 calories 1/4 of a pepperoni pizza plus a who

yulyashka [42]

Answer:

Correct choice is D (In a whole pepperoni pizza are 660 calories, in in a whole ham and pineapple pizza are 580 calories).

Step-by-step explanation:

Let x calories be the number of calories a whole pepperoni pizza contains and y calories be the number of calories a whole ham and pineapple pizza contains.

1. If half a pepperoni pizza plus three fourths of a ham and pineapple pizza contains 765 calories, then

$\dfrac{1}{2}x+\dfrac{3}{4}y=765.$

2. If 1/4 of a pepperoni pizza plus a whole ham and pineapple pizza contains 745 calories. then

$\dfrac{1}{4}x+y=745.$

3. Multiply each equation by 4 and get a system of two equations:

$\left\{\begin{array}{l}2x+3y=3060\\x+4y=2980\end{array}\right.$

From the second equation $x=2980-4y$ , then

$2(2980-4y)+3y=3060,\\ \\5960-8y+3y=3060,\\ \\-8y+3y=3060-5960,\\ \\-5y=-2900,\\ \\y=580.$

Then

$x=2980-4\cdot 580=2980-2320=660.$

6 0

3 years ago

Divide 8 by 10, then multiply g by the result

algol13

Answer:

80 Ikaw na bahala kung lalagyan Mona ng g yan o hindi

5 0

3 years ago

PLEASEEE HELPPPPPPP 15 POINTS

anygoal [31]

The equivalent to (1/3)^3 is

(1/3) x (1/3) x (1/3) = .<span>037
</span>
The answer is 1/27 or 0.37.

3 0

3 years ago

so There are 17 girls and 119 boys on a class field trip to the museum. The students need to be broken up into the largest possi

Step2247 [10]

1 student in each group with 126 groups in total

8 0

3 years ago

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

4 years ago