Answer:
..................
Step-by-step explanation:
jk im still working on qit
what............there’s no pic
For this case we have that by definition, the point-slope equation of a line is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have two points:

We found the slope:

Thus, the equation is of the form:

We substitute one of the points and find "b":

Finally, the equation is:

Answer:

Answer:
(5,-4) and (-5,6)
Step-by-step explanation:
Given:

Solve it. First, express y in terms of x from the second equation:

Substitute it into the first equation:

Apply zero product property:

So,

When
then 
When
then 
We get two solutions: (5,-4) and (-5,6)