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2 years ago

I need help ASAP PLEASE

Mathematics

1 answer:

White raven [17]2 years ago

7 0

A) y= x+1
b) y= -2/3x-5
c) y=-1/2x+12
d) y= 4x-3/2
According to my calculations all the answers should be correct.

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Write the equation for the following relation. R = {(x, y): (4, 5), (8, 7), (12, 9), (16, 11), . . .} and show work

timama [110]

Let

A(4,5) B(8,7) C(12,9) D(16,11)

1) Find the slope AB

m=(y2-y1)/(x2-x1)

m=(7-5)/(8-4)=0.5

2) Find the slope BC

m=(9-7)/(12-8)=0.5

3) Find the slope CD

m=(11-9)/(16-12)=0.5

The points represent a linear function

Find the equation of the line with m=0.5 and the point A(4,5)

we know that

y-y1=m*(x-x1)

y-5=0.5*(x-4)

y=0.5*x-2+5

y=0.5*x+3

therefore

the answer is

The equation is equal to y=0.5*x+3

8 0

2 years ago

Annabella time for a race was 24.2 seconds. Another runnee's time was 6.43 seconds faster write and evaluate an equation with to

liberstina [14]

Answer:

Step-by-step explanation:

Given Annabella time for a race is 24.2 seconds, if another runnee's time was 6.43 seconds faster, then the time taken for another runnee's time will be 24.2 - 6.43 = 17.77secs.

Let a variable X be the difference between annabelle's time and the other runners time.

X = annabelle's time - other runners time.

X = 24.2 - (24.2 - 6.43)

X = 24.2-24.2+6.43

X = 6.43seconds

Hence the expression between annabelle's time and the other runners time is X = 24.2 - (24.2 - 6.43)

The difference between annabelle's time and the other runners time is 6.43seconds

8 0

2 years ago

Mr. Crosby's is driving jack, cassidy, and victor to the library. Jake lives 1/4 miles from the library, cassidy lives 1)3 mile

irakobra [83]

Answer:

5/8, 1/3, 1/4

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Determine whether the equation is exact. If it is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e

umka21 [38]

Answer:

$F(t,y)=(2+7e^t)y+3(1-t)e^t +C$

Step-by-step explanation:

You have the following differential equation:

$e^t(7y-3t)dt+(2+7e^t)dy=0$

This equation can be written as:

$Mdt+Ndy=0$

where

$M=e^t(7y-3t)\\\\N=(2+7e^t)$

If the differential equation is exact, it is necessary the following:

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}$

Then, you evaluate the partial derivatives:

$\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}$