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Alinara [238K]
3 years ago
12

Is this a quadrilateral , trapezoid, parallelogram , rhombus, rectangle , or square .

Mathematics
2 answers:
Vika [28.1K]3 years ago
5 0
It is a rectangle and parallelogram.
It is is parallelogram because opposite sides are congruent.
Volgvan3 years ago
5 0
It is a <span>quadrilateral for having 4 sides.. not all are equal so its not a square.</span>
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50 meters to 20 meters<br><br> Increase or decrease?
Aleonysh [2.5K]

Answer:

Decrease

Step-by-step explanation:

50 is bigger than 20, so it's decreasing and the units are the same.

3 0
3 years ago
Complete the missing value in the solution to the equation:<br> 8x + x - y = 2x + 12 + 2y<br> ( ,3
Digiron [165]
The answer to the missing value is X = 3

6 0
3 years ago
Posting a screenshot.
Anna71 [15]
Since 6 is positive, it's (x+blank)^2

6/2=3, and (x+3)^2 = x^2+6x+9. We have x^2+6x-2, so we have to add 9 to both sides to get (x+3)^2-2=9, then subtract 9 from both sides to get
(x+3)^2-11=0, or (x+3)^2=11. Square root both sides to get x+3=sqrt(11), and x=sqrt(11)-3, which is approximately 0.32
8 0
3 years ago
Line ℓ1 has the equation
aleksley [76]

Answer:

\sqrt{2} units

Step-by-step explanation:

The Line 1 has equation x + y = 5 ....... (1) , and  

Line 2 has equation x + y = 3 .......... (2)

Now, we have to find the perpendicular distance between line 1 and line 2.

We can say that (3,0) is a point on line 2 as it satisfies the equation (2).

Now, the perpendicular distance from point (3,0) to the line 1 will be given by the formula

\frac{|3 + 0 - 5|}{\sqrt{1^{2}+ 1^{2}}} = \frac{2}{\sqrt{2}} = \sqrt{2} units (Answer)

We know that the perpendicular distance from any external point (x_{1},y_{1}) to a given straight line ax + by + c = 0 is given by the formula \frac{|ax_{1} + by_{1} + c|}{\sqrt{a^{2} + b^{2}}}.

3 0
3 years ago
Which graph represents 7x-2y_&lt;5
serious [3.7K]

Answer:.

Step-by-step explanation:.

8 0
3 years ago
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