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3 years ago

Please help me! I need this to complete my math hw

Mathematics

1 answer:

babymother [125]3 years ago

4 0

Answer:

Step-by-step explanation:

You "complete the square" by adding the square of half the x-term coefficient. Here, that is ...

((-2)/2)² = 1 . . . . value added to complete the square

If you want to keep 0 on the right, you must also subtract this value:

x² -2x -36 = 0

x² -2x +1 -36 -1 = 0 . . . . . . add and subtract 1 on the left

(x -1)² -37 = 0 . . . . . . . . . . . written as a square

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Pls help!!!! Rewrite the expression. <br> 4+4+5x2x5+(3+3+3)x6x6+2+2

Paha777 [63]

Answer:

386

Step-by-step explanation:

4+4+5x2x5+(3+3+3)x6x6+2+2

=4+4+5x2x5+9x6x6+2+2

=4+4+50+324+2+2

=386

8 0

3 years ago

A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo

defon

Answer:

a) The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

b) $P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

c) $P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

$X \sim Unif (a= 10, b =12)$

Part a

The expected value is given by:

$E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11$

The variance is given by:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333$

And the standard deviation is just the square root of the variance and we got:

$Sd(x) = \sqrt{0.3333}= 0.5774$

Part b

For this case we want this probability:

$P(X$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}, a \leq x \leq b$

And using this function we got:

$P(X$

Part c

For this case we want this probability:

$P(X>10.5)$

And using the complement rule and the cumulative distribution function we got:

$P(X>10.5)= 1-P(X$

3 0

3 years ago

What are the coefficients of the like terms in this expression? 18x - 9xy + 12x

likoan [24]

Steps to my answer:

18x-9xy+12x

Add similar elements together, your answer comes out to be:
=30x-9xy
I hope this is what you were looking for! :)

6 0

3 years ago

Read 2 more answers

Evaluate 10x^2y^-2 for x = –1 and y = –2a) 10(2)^0b) 2 1/2c) 40d) 5/8

timurjin [86]

10x^2y^-2 = 10 x (-1)^2 x (-2)^-2 = 10 x 1 x 1/4 = 10/4 = 2 1/2

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3 years ago

Money managers:

tatyana61 [14]

Answer:

Step-by-step explanation:

3 0

3 years ago