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gayaneshka [121]

3 years ago

6

A 120-pound person uses 3 calories per minute walking at a 20 min/mile pace. approximately, how many miles would a person have t

o walk to burn off a scoop of ice cream (175 calories)? 1.5 miles 2.0 miles 2.5 miles 3.0 miles

2 answers:

lora16 [44]3 years ago

6 0

He would have to walk 175/3 minutes to burn off the ice cream. If you divide this by 20, you could find how many miles he would need to walk. 175/3/20 Which comes to roughly 2.9. If you round up, it is 3 miles. Please mark Brainliest!!!

rjkz [21]3 years ago

4 0

Answer : A person walk to burn off a scoop of ice cream is, 3.0 miles

Step-by-step explanation :

First we have to determine the time taken to burn calories.

As, 3 calories burn in 1 minutes

So, 175 calories burn in $\frac{175\text{ calories}}{3\text{ calories}}\times 1\text{ minutes}=58.33\text{ minutes}$

Now we have to determine the distance traveled by a person.

As, the distance traveled in 20 minutes = 1 mile

So. the distance traveled in 58.33 minutes = $\frac{58.33\text{ minutes}}{20\text{ minutes}}\times 1\text{ mile}=2.916\text{ mile}\approx 3.0\text{ mile}$

Thus, a person walk to burn off a scoop of ice cream is, 3.0 miles.

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A machine fills containers with a particular product. Assume the filling weights are normally distributed with a variance of 0.1

Ghella [55]

Answer:

$z=-0.674$

And if we solve for $\mu$ we got

$\mu=12 +0.674*0.4=12.270$

So then the mean is $'mu = 12.270$ for this case.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sqrt{0.16}= 0.4)$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>12)=0.85$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.85 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.85

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.674$

And if we solve for $\mu$ we got

$\mu=12 +0.674*0.4=12.270$

So then the mean is $'mu = 12.270$ for this case.

8 0

3 years ago

1. De una encuesta realizada a 120 personas sobre el consumo de albaricoque, banana y coco se obtuvieron el siguiente resultado.

Pachacha [2.7K]

Answer:

El número de personas que consumen dos productos es 30.

Step-by-step explanation:

El primer paso para resolver el problema es realizar los gráficos de los eventos (agregaré como archivo adjunto el gráfico del ejercicio).

En el gráfico podemos ver 7 regiones :

A : Personas que consumen sólo albaricoque.

B : Personas que consumen sólo banana.

C : Personas que consumen sólo coco.

D : Personas que consumen sólo albaricoque y coco.

E : Personas que consumen las tres frutas (albaricoque, banana y coco).

F : Personas que consumen sólo banana y coco.

G : Personas que consumen sólo albaricoque y banana.

Ahora, debemos escribir las ecuaciones que nos brinda el ejercicio :

La encuesta se realizó a 120 personas y se sabe que todas las personas consumen un producto ⇒

$A+B+C+D+E+F+G=120$ (I)

''El número de personas que consumen sólo albaricoque y coco es la mitad de las que consumen sólo albaricoque'' ⇒

$D=\frac{A}{2}$ (II)

''El número de personas que consumen sólo banana es el doble de las personas que consumen sólo albaricoque y banana más sólo banana y coco'' ⇒

$B=2.(G+F)$ (III)

Finalmente : ''El número de personas que consumen sólo coco más los que consumen los tres productos es 30'' ⇒

$C+E=30$ (IV)

Finalmente obtenemos el siguiente sistema de ecuaciones :

$A+B+C+D+E+F+G=120\\D=\frac{A}{2}\\B=2.(G+F)\\C+E=30$

El número de personas que consumen dos productos es :

$D+F+G$

Entonces, resolvemos escribiendo la primera ecuación conmutando los términos :

$A+B+C+E+D+F+G=120$ (V)

De (II) se obtiene :

$2D=A$ (VI)

Usamos (VI), (III) y (IV) en (V) ⇒

$2D+2(G+F)+30+D+F+G=120$ ⇒

$2D+2G+2F+30+D+F+G=120$

$3D+3F+3G=90$

Dividiendo esta última ecuación por ''3'' obtenemos :

$D+F+G=30$

Que es el número de personas que consumen dos productos.

Es muy conveniente seguir el desarrollo del ejercicio mirando el gráfico que adjunto.

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