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3 years ago

Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?

Mathematics

1 answer:

maks197457 [2]3 years ago

5 0

Answer:

1) x³-y³ = (x-y)(x²-xy+y²)

2)x²-y² =(x-y)(x+y)

3)x-y = (x-y)

hcf = (x-y)

lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)

Step-by-step explanation:

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3 years ago

Can I have help with the question

sleet_krkn [62]

Answer:

Midpoint = (3.5, 4.5)

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Step-by-step explanation:

[] We can solve this using the midpoint formula:

-> See attached

[] Plug-in our coordinates and solve:

$(\frac{7+0}{2} ,\frac{0+9}{2} )=(\frac{7}{2} ,\frac{9}{2} )=(3.5,4.5 )$

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-> We will use slope-intercept form, see attached

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Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Yuliya22 [10]

Answer:

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3 years ago

Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?​

Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?