The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches

So, length of sides will be,

2.57 x 10^4 is 5 times larger than 2.57 x 10^-1
Answer:
x =5
Step-by-step explanation:
We can use proportions to solve this problem. Put the side of one triangle over the same side of the other triangle.
x 4
------ = ----------
40 32
Using cross products
32x = 4*40
32x = 160
Divide each side by 32
32x/32 =160/32
x =5
Answer:
Can you add the box plots pls
Step-by-step explanation:
Answer: D
Step-by-step explanation: