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Komok [63]
3 years ago
8

An 8th grade class project involves decorating a rectangular box with the following dimensions.

Mathematics
1 answer:
Margarita [4]3 years ago
5 0

Answer:1500

Step-by-step explanation: so i got the anwser 1539.2 and just rounded to the nearest hundredth which is 1500 hopefully it helps!

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Combine the like terms to create an equivalent expression: <br><br>−4p+(−6p)
Y_Kistochka [10]

THE ANSWER IS -10P.

Step-by-step explanation:

USING BY MULTIPLICATION RULE.

minus × plus = minus

then minus × minus = plus.

so we add the 4p+6p= -10p.

why -10p is come it means THE BIGGER NUMBER SIGN IS MINUS. So it's comes -10p.

<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELP</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
Iona wrote out the description of each step for her multiplication of the binomial and trinomial (2x – 3)(5x2 – 2x + 7)
Olin [163]

Steps for multiplying the given binomial and trinomial (2x-3)\times (5x^{2}-2x+7) are:

Step 1: 2x\times (5x^{2}-2x+7)-3 \times (5x^{2}-2x+7)

Step 2: 10x^{3}-4x^{2}+14x-15x^{2}+6x-21

Step 3: 10x^{3}-19x^{2}+20x-21

7 0
3 years ago
Read 2 more answers
H divided (3+y) what is the answer need asp
Hunter-Best [27]

Answer:

H Divided by (3+y) is equivalent to H/(3+y)

Step-by-step explanation:

Hope This Helps!

6 0
2 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = &lt;-5, -4&gt;, v = &lt;-4, -3&gt; (1 point)
sesenic [268]

Angle between u = -5i-4j , v=-4i-3j is x =0° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3>  or , u = -5i-4j , v=-4i-3j

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

u.v =|u|(|v|)cosx , where x is angle between u & v !

⇒ u.v =|u|(|v|)cosx

⇒ cosx =\frac{u.v}{|u|(|v|)}

Now , u.v = (-5i-4j)(-4i-3j)

⇒ u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)

⇒ u.v = 20+12            { i(j) = j(i) =0  }

⇒ u.v = 32

Now , Modulus of any vector  r = xi+yj is |r| = \sqrt{x^{2}+y^{2}} So ,

|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5

Putting all these values in equation cosx =\frac{u.v}{|u|(|v|)} we get:

⇒ cosx =\frac{32}{5(\sqrt{41})}

⇒ cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})

⇒ x =cos^{-1}(1)                 { cos0 = 1  }

⇒ x =0°

Therefore , Angle between u = -5i-4j , v=-4i-3j is x =0° .

8 0
3 years ago
Owen is signing up for a gym membership with a one time fee to join and then a monthly fee to remain a member. The one time fee
boyakko [2]

Answer:

Use mathpapa it helps a lot

Step-by-step explanation:

Mathpapa.com

6 0
3 years ago
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