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Inessa [10]
4 years ago
12

The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and

Mathematics
2 answers:
a_sh-v [17]4 years ago
7 0

Answer:

No, that is not possible

Explanation:

P = 2L + 2W

Insert numbers into equation

p=(2)(20)+(2)(11)

Step 1: Simplify both sides of the equation.

p=(2)(20)+(2)(11)

p=40+22

p=(40+22)(Combine Like Terms)

p=62

p=62

The perimeter is 62, not 64, so the perimeter can't be 64 if the length 20 and the width is 11.

GaryK [48]4 years ago
3 0

Answer:NO

Step-by-step explanation:

P=2L+2w

P=2×20+2×11

P=40+22

P=62

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If y=29,find x<br><br> y=(x+2)(x-2)<br> Please show working
Ainat [17]

Answer:

x=±sqrt (33)

Step-by-step explanation:

y=(x+2)(x-2)

29=x^2-4. x^2=33, x=±sqrt (33)

6 0
3 years ago
Read 2 more answers
Calen is comparing the prices per child for hosting a birthday at Mr. Bob’s Buffet and Sally’s Pizza Safari.
Bas_tet [7]

Answer:

The cost per child is $2.50 more at Mr. Bob’s Buffet than it is at Sally’s Pizza Safari

Step-by-step explanation:

<u><em>The missing table in the attached figure</em></u>

step 1

Find the cost per child at Mr. Bob’s Buffet

we know that

The cost per child or unit rate is the same that the slope of the linear equation

From the graph take two points

(0,0) and (4,60)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{60-0}{4-0}

m=\$15\ per\ child

step 2

Find the cost per child at Sally’s Pizza Safari.

From the data in the table

we have

(4,50) and (6,75)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{75-50}{6-4}

m=\$12.5\ per\ child

step 3

<u><em>Verify each statement</em></u>

case A) The cost per child is $2.50 more at Mr. Bob’s Buffet than it is at Sally’s Pizza Safari

The statement is true

Because

The cost per child is $15 at Mr. Bob’s Buffet

The cost per child is $12.50 at Sally’s Pizza Safari

The difference is $2.50 per child

case B) The cost per child is $10.00 more at Mr. Bob’s Buffet than it is at Sally’s Pizza Safari

The statement is false (see the explanation)

case C) The cost per child is $15.00 more at Mr. Bob’s Buffet than it is at Sally’s Pizza Safari

The statement is false (see the explanation)

case D) The cost per child is $5.00 more at Mr. Bob’s Buffet than it is at Sally’s Pizza Safari.

The statement is false (see the explanation)

7 0
3 years ago
What are the vertex and x-intercepts of the graph and function given below? x2 - 2x - 35
dexar [7]
X-int:(7,0)(-5,0)
Vertex:minimum(1,-36)
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4 years ago
Solving for a Variable when multiple variables present
Nostrana [21]

Answer:

The answere is a=y-x

I hope this help

5 0
3 years ago
Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30
TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

-7, -3, 1, 5, . . .

An arithmetic sequence has a constant difference d and is defined by

a_n=a_1+\left(n-1\right)d

\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n

-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4

\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

d=4

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=-7

as

a_n=a_1+\left(n-1\right)d

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=4\left(n-1\right)-7           ∵ d=4

\mathrm{Arithmetic\:sequence\:sum\:formula:}

n\left(a_1+\frac{d\left(n-1\right)}{2}\right)

\mathrm{Plug\:in\:the\:values:}

n=30,\:\space a_1=-7,\:\spaced=4

=30\left(-7+\frac{4\left(30-1\right)}{2}\right)

=30\left(58-7\right)     ∵  \frac{4\left(30-1\right)}{2}=58

=30\cdot \:51

=1530           ∵  \mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

a_n=4\left(n-1\right)-7

n = 30

\sum _{n=1}^{30}\:4\left(n-1\right)-7

=\sum _{n=1}^{30}4n-11

\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n

=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11

as

\sum _{n=1}^{30}4n=1860

and

\sum _{n=1}^{30}11=330

so

=1860-330

=1530

7 0
4 years ago
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