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vichka [17]
3 years ago
9

Please help. 24 points!!

Mathematics
1 answer:
Lina20 [59]3 years ago
6 0

The given function is,

f(x)= \frac{2x-1}{x+5}.

Or, y= \frac{2x-1}{x+5}

To find the inverse of a function, first step is to switch x and y. Therefore,

x= \frac{2y-1}{y+5}

Next stpe is to solve the above equation for y t get the inverse f f(x). Hence, multiply each sides by y + 5 to get rid of fraction form. So,

x*(y+5)= \frac{2y-1}{y+5}*(y+5)

xy + 5x = 2y - 1

xy = 2y - 1 - 5x Subtract 5x from each sides to isolate y.

xy - 2y = -5x - 1 Subtract 2y from each sides.

y(x - 2) = -5x -1 Take out the common factor y.

\frac{y(x-2)}{(x-2)} =\frac{(-5x-1)}{(x-2)} Divide each sides by x-2.

y=\frac{(-5x-1)}{(x-2)}

So, f^-1(x)=\frac{-5x-1}{x-2}

Now when we will compare f^-1(x)=\frac{-5x-1}{x-2} with f^-1(x)=\frac{ax+b}{cx+d} then we will get a = -5, b = -1, c = 1 and d=-2

So, \frac{a}{c} =\frac{-5}{1} =-5

Hope this helps you!

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