if the upper number got power of negative it will go down and the down will go up
So that,
power of 1 can no need to write
2/5(d−10)−23(d+6)25(d−10)−23(d+6) is
1 answer:
Simplify 
(d - 10) to 
:
\frac{2(d - 10)}{5} [/tex] - 23(d + 6) x 25(d - 10) - 23(d + 6)
Simplify 23(d + 6) x 25(d - 10) to 575(d + 6)(d - 10) :
\frac{2(d - 10)}{5} [/tex] - 575(d + 6)(d - 10) - 23(d + 6)
Then Expand :
\frac{2(d - 10)}{5} [/tex] - 575
+ 5750d - 3450d + 34500 - 23d - 138
Now Collect Like Terms :
\frac{2(d - 10)}{5} [/tex] - 575 + (5750d - 3450d + 34500 - 23d) + (34500 - 138)
Answer :
\frac{2(d - 10)}{5} [/tex] - 575 + 2277d + 34362
\frac{2(d - 10)}{5} [/tex] - 23(d + 6) x 25(d - 10) - 23(d + 6)
Simplify 23(d + 6) x 25(d - 10) to 575(d + 6)(d - 10) :
\frac{2(d - 10)}{5} [/tex] - 575(d + 6)(d - 10) - 23(d + 6)
Then Expand :
\frac{2(d - 10)}{5} [/tex] - 575
Now Collect Like Terms :
\frac{2(d - 10)}{5} [/tex] - 575
Answer :
\frac{2(d - 10)}{5} [/tex] - 575
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