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allochka39001 [22]
3 years ago
12

Which equation is an equation of a circle with radius of 10 cm and center at (-3, 6)?

Mathematics
1 answer:
Musya8 [376]3 years ago
7 0
The equation for a circle is 
(x-h)^2 + (y-k)^2 = r^2
(-3,6)
-3 is h 
6 is k 

(x+3)^2 + (y-6)^2 = 10^2
10^2 = 100 

(x+3)^2 + (y-6)^2 =100
The answer is B!
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A farmer plants wheat in a rectangular plot of land having a length of 7260 feet and a width of
Leto [7]

Answer:

  $6000

Step-by-step explanation:

There are 43560 square feet in an acre. The profit is expected to be ...

  (7260 ft)(1200 ft) × ($30)/(43560 ft²) = $6000

_____

The area of the plot is 200 acres.

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2 years ago
F(-4) if f(x) =x to the power of 2 +8
Rufina [12.5K]
10 :) I had this, EZ now :)
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Subtract x3 – 7x2 + 3 from the sum of - 3x3 + x2 and – x2 + 4x - 3.
Vesnalui [34]

Answer:

x3 – 7x2 + 3------  x3 - 7x2 + 3

3x3 + x2-----------x2 • (3x + 1)

x2 + 4x - 3------------ x2 + 4x - 3

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

 ((x3) -  7x2) +  3

Step  2  :

Polynomial Roots Calculator :

2.1    Find roots (zeroes) of :       F(x) = x3-7x2+3

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  1  and the Trailing Constant is  3.

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,3

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -5.00      

     -3       1        -3.00        -87.00      

     1       1        1.00        -3.00      

     3       1        3.00        -33.00    

Hope this helps.

3 0
3 years ago
Read 2 more answers
Volume of a rectangular Pyramid that has a height of 9 cm length of 8 cm and a width of 9 cm
Alexus [3.1K]

Answer:

length = 8 cm

breadth = 9 cm

height = 9cm

Volume = ?

now,

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5 0
3 years ago
1. Two object accumulated a charge of
In-s [12.5K]

Answer:

The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

As

Two object accumulated a charge of  4.5 μC and another a charge of 2.8  μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8  μC = 2.8 × 10⁻⁶  C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

7 0
3 years ago
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