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Studentka2010 [4]
3 years ago
7

A term for a geometric figure that is enclosed by a circle.

Mathematics
2 answers:
Verizon [17]3 years ago
6 0
A geometric figure enclosed by a circle is called an inscribed figure.
Daniel [21]3 years ago
5 0

we know that

Circumcircle:

In geometry, the circumscribed circle or circumcircle of a polygon is a circle which passes through all the vertices of the polygon

so, any figure enclosed by circle is called as circumcircle

For exp:

The figure attached

we can see that triangle is inside circle

so,

a geometric figure that is enclosed by a circle is circumcircle

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Petes dog weighed 30 pounds it then lost 16% of it's weight how much did pete lose
Paraphin [41]

Answer:

4.8 pounds!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!


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3 years ago
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The change in altitude of a bird after 2 __ 1 2 seconds was –41 __ 1 4 feet. What was the average change in altitude of the bird
svlad2 [7]

Answer:

Average\ Change = -1\frac{7}{10} ft/s

Step-by-step explanation:

Given

Altitude\ Change = -4\frac{1}{4} \ ft

Time = 2\frac{1}{2}\ s

Required

Determine the average change

This is calculated as follows:

Average\ Change = \frac{Altitude\ Change}{Time}

This gives:

Average\ Change = \frac{-4\frac{1}{4}}{2\frac{1}{2}}

Average\ Change = -4\frac{1}{4}/2\frac{1}{2}

Convert to improper fractions

Average\ Change = -\frac{17}{4}/\frac{5}{2}

Convert to multiplication

Average\ Change = -\frac{17}{4}*\frac{2}{5}

Average\ Change = -\frac{17}{2}*\frac{1}{5}

Average\ Change = -\frac{17}{10}

Average\ Change = -1\frac{7}{10} ft/s

8 0
3 years ago
A bowling leagues mean score is 197 with a standard deviation of 12. The scores are normally distributed. What is the probabilit
Bond [772]

Answer:

0.281 = 28.1% probability a given player averaged less than 190.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A bowling leagues mean score is 197 with a standard deviation of 12.

This means that \mu = 197, \sigma = 12

What is the probability a given player averaged less than 190?

This is the p-value of Z when X = 190.

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 197}{12}

Z = -0.58

Z = -0.58 has a p-value of 0.281.

0.281 = 28.1% probability a given player averaged less than 190.

8 0
3 years ago
Can someone please help me with these two questions! :( ill mark u as brainlest
Maslowich

Answer:

1.A by SSS axiom

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Answer:

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