Answer: Triangles BCA and DAC are congruent according to the Angle-Side-Angle (ASA) Theorem.
Step-by-step explanation:
Given : ABCD is a parallelogram.
That is, AB ║ CD and AD ║BC
We have to prove that: AB≅CD and AD≅BC
Proof:
Construct diagonal AC in the parallelogram ABCD.
Since, AC ≅ AC ( reflexive)
∠ BAC ≅ ∠ DCA ( By the alternative interior angle theorem)
∠ BCA ≅ ∠ DAC ( By the alternative interior angle theorem)
⇒ Δ BCA ≅ Δ DAC ( By ASA congruence postulate )
⇒ AB≅CD as well as AD≅BC ( BY CPCTC )
Thus, the opposite side of the parallelogram are congruent.
$3000 x .04 =$120
$120 x 10 =$1200
$3000+1200= $4200 Total
10x=7
x=7/10, you could work backwards to find y if it asked
Answer:
Area of triangle = 1/2*b*h

Answer: BC=18
DG=6
Step-by-step explanation: well we have to use similarity. and that means setting up proportions so... 15/10 = BC/12 10BC=180, BC=18
9/18=DG/12 (we put 18 because it equals BC)
hope this helped!!